Question

Factorise :- ${6x}^{2} - 19x - 7$​

Answer 1

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$\small\tt{6x^{2} - 19x - 7\: }$

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$\bf\blue{\underline{\boxed{Solution}}}$

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$\small\tt{6x^{2} - 19x - 7\: }$

$\small\tt{6x^{2} -21x +2x -7}$

$\small\tt{3x(2x-7) +1 (2x-7)}$

$\small\tt{(3x+1)\:(2x-7)}$

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$\small\tt{3x\:+1\:=\:0\:}$

$\small\tt\red{\underline{\boxed{x\:=\:{\frac{-1}{\:\:\:3}}}}}$

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$\small\tt{2x\:-7\:=\:0\:}$

$\small\tt\red{\underline{\boxed{x\:=\:{\frac{7}{2}}}}}$

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$\bf\blue{\underline{\boxed{Hope\:It\: Help\:You}}}$

Answer 2

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Factorise :- ${6x}^{2} - 19x - 7$

$\huge\sf \green{\underline{\red{\underline{\blue{\underline{\orange{Solution:-}}}}}}}$

${6x}^{2} - (19)x - 7$

${6x}^{2} - ( - 2 + 21)x - 7$

Apply distributive property:

${6x}^{2} + 2x - 21x - 7$

Now,

Separate the factor out of the Greater Common Factor from each group:

Now,

Make a group of first two terms & last two terms.

$( {6x}^{2} + 2x) - 21x - 7$

Again,

Separate the factor out the G.C.F. ( Greatest Common Factor ) from each group.

$2x(3x + 1) - 7(3x + 1)$

Therefore,

The Factorisation of ${6x}^{2} - 19x - 7$ is $(3x+1) (2x-7)$