Question

Factorise -

$81(x + 1) {}^{2} + 90(x + 1)(y + 2) + 25(y + 2) {}^{2}$
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Answer 1

Answer:

Factories form of the expression is 81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)(9x+5y+19)81(x+1)

2

+90(x+1)(y+2)+25(y+2)

2

=(9x+5y+19)(9x+5y+19)

Step-by-step explanation:

Given : Expression 81(x+1)^2+90(x+1)(y+2)+25(y+2)^281(x+1)

2

+90(x+1)(y+2)+25(y+2)

2

To find : Factories the expression?

Solution :

The given expression 81(x+1)^2+90(x+1)(y+2)+25(y+2)^281(x+1)

2

+90(x+1)(y+2)+25(y+2)

2

is in the form of a^2+2ab+b^2a

2

+2ab+b

2

in which

a=9(x+1)a=9(x+1)

b=5(y+2)b=5(y+2)

We know, a^2+2ab+b^2=(a+b)^2a

2

+2ab+b

2

=(a+b)

2

Substitute a and b,

(9(x+1))^2+2(9(x+1))(5(y+2))+(5(y+2))^2=((9(x+1))+(5(y+2)))^2(9(x+1))

2

+2(9(x+1))(5(y+2))+(5(y+2))

2

=((9(x+1))+(5(y+2)))

2

81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+9+5y+10)^281(x+1)

2

+90(x+1)(y+2)+25(y+2)

2

=(9x+9+5y+10)

2

81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)^281(x+1)

2

+90(x+1)(y+2)+25(y+2)

2

=(9x+5y+19)

2

81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)(9x+5y+19)81(x+1)

2

+90(x+1)(y+2)+25(y+2)

2

=(9x+5y+19)(9x+5y+19)

Therefore, factories form of the expression is 81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)(9x+5y+19)81(x+1)

2

+90(x+1)(y+2)+25(y+2)

2

=(9x+5y+19)(9x+5y+19)

Step-by-step explanation:

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