Question

Factorise
$9 {y}^{2} - 66yz + 121 {z}^{2}$
​

Answer 1

Answer:

$(a + b {)}^{2} = {a}^{2} + {b}^{2} - 2ab$

$= > (3y {)}^{2} + (11z {)}^{2} - 23y \times 11$

$= > (3y - 11z {)}^{2}$

Answer 2

Answer:

$\huge\bold\red{ANSWER}$

Step-by-step explanation:

$\large{\underline{\rm{\red{SOLUTION :}}}}$

$\implies \sf \green {9y^2-66yz+121z^2}\\ \implies \sf \green {(3y)^2-2\times3\times11\times yz+(11z)^2}\\ \implies \sf \green {(3y-11z)^2}$