Question

factorise
$9a {}^{2} + 3a - 8b - 64b {}^{2}$
please answer it fast
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Answer 1

Solution :-

Given expression is 9a²+3a-8b-64b²

It can be written as

9a²-64b²+3a-8b

=> (9a²-64b²)+(3a-8b)

=> [(3a)²-(8b)²]+(3a-8b)

=> (3a+8b)(3a-8b)+(3a-8b)

=> [(3a+8b)(3a-8b)] + [(3a-8b)×1]

Since, (x+y)(x-y) = x²-y²

Where ,x = 3a and y = 8b

=> (3a-8b)(3a+8b+1)

Answer :-

9a²+3a-8b-64b² = (3a-8b)(3a+8b+1)

Used Formulae:-

• (x+y)(x-y) = x²-y²

Answer 2

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Given expression is 9a²+3a-8b-64b²

It can be written as

9a²-64b²+3a-8b

=> (9a²-64b²)+(3a-8b)

=> [(3a)²-(8b)²]+(3a-8b)

=> (3a+8b)(3a-8b)+(3a-8b)

=> [(3a+8b)(3a-8b)] + [(3a-8b)x1]

Since, (x+y)(x-y)=x²-y²

Where ,x= 3a and y = 8b => (3a-8b)(3a+8b+1)

Answer :

9a²+3a-8b-64b² = (3a-8b)(3a+8b+1)

Used Formulae:

• (x+y)(x-y)=x²-y²