Question

Factorise:
${a}^{2} - (2a + 3b {)}^{2}$
​

Answer 1

Answer:

a²-(2a+3b) ²

a²-(4a²+12ab+9b²) ..... by using identity ( a+ b) ²= a²+2ab+b²

therefore, a²-4a²+12ab+9b²

-3a²+12ab+9b²

-3(a²+4ab+3b²)..... by taking common

Answer 2

Answer:

Question :-

➠ a² - (2a + 3b)²

Formula used :-

➪ a² - b²

➔ (a + b) (a - b)

Answer :-

➠ a² - (2a + 3b)²

➻ (a)² - (2a + 3b)²

➻ (a - 2a - 3b) (a + 2a + 3b)

➻ (- a - 3b) (3a + 3b)

➻ - 3(a + 3b) (a + b)

∴ The value of a² - (2a + 3b)² is - 3(a + 3b) (a + b)