Question

Factorise:-
$a {}^{2}bx + 2a {}^{2}cx - 2aby - 4acy + bz + 2cz$

Answer 1

Answer :

Now,

a²bx + 2a²cx - 2aby - 4acy + bz + 2cz

= a²x (b + 2c) - 2ay (b + 2c) + z (b + 2c)

= (b + 2c) (a²x - 2ay + z),

which is the required factorization.

#MarkAsBrainliest

Answer 2

Answer:

Step-by-step explanation:

• Answer :
• Now,
• a²bx + 2a²cx - 2aby - 4acy + bz + 2cz
• = a²x (b + 2c) - 2ay (b + 2c) + z (b + 2c)
• = (b + 2c) (a²x - 2ay + z),
• which is the required factorization.
• #MarkAsBrainliest