Question

factorise:
${(a - 2b)}^{2} - 4a + 8b$
Factorise by grouping​

Answer 1

Answer:

{(a-2b)^2-4a+8b}

={(a-2b)^2-4(a-2b)}

=(a-2b)(a-2b-4)

Answer 2

Step-by-step explanation:

$(a - 2b) {}^{2} - 4a + 8b \\ (a - 2b) {}^{2} - 4(a - 2b) \\ (a - 2b) \times (a - 2b - 4)$