Math, asked by anshikakumari20, 1 year ago

factorise:
 {a}^{6}  - 7 {a}^{3}  - 8

Answers

Answered by graxx
9
Hi there

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Answered by Anonymous
4
Hello Friend....

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The answer of u r question is....

 {a}^{6} -7 {a}^{3} - 8

Ans:

Given,

a^6 - 7a^3-8

= a^6 + a^3 - 8a^3 - 8

= a^3 × (a^3 + 1) - 8 (a^3 + 1)

= (a^3 + 1) × (a^3 - 8)

=(a+1) × (a^2 - a+1) × (a-2) × (a^2+2a+4)...

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