factorise:
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Hope this will help you
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Hello Friend....
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The answer of u r question is....
Ans:
Given,
a^6 - 7a^3-8
= a^6 + a^3 - 8a^3 - 8
= a^3 × (a^3 + 1) - 8 (a^3 + 1)
= (a^3 + 1) × (a^3 - 8)
=(a+1) × (a^2 - a+1) × (a-2) × (a^2+2a+4)...
_____________________________
_____________________________
Thank you..⭐️⭐️⭐️
_____________________
_____________________
The answer of u r question is....
Ans:
Given,
a^6 - 7a^3-8
= a^6 + a^3 - 8a^3 - 8
= a^3 × (a^3 + 1) - 8 (a^3 + 1)
= (a^3 + 1) × (a^3 - 8)
=(a+1) × (a^2 - a+1) × (a-2) × (a^2+2a+4)...
_____________________________
_____________________________
Thank you..⭐️⭐️⭐️
SJking1:
hi
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