Question

Factorise
${(a + b)}^{3} - 8$
Please answer it
​

Answer 1

Answer:

answers....

....

..

..

Answer 2

Step-by-step explanation:

${(a + b)}^{3} - 8 \\ = {(a + b)}^{3} - {(2)}^{3} \\ = {x}^{3} - {y}^{3} \\ = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ = [(a + b )- 2][ {(a + b)}^{2} + ab + {(2)}^{2} ] \\ = (a + b - 2)( {a}^{2} + 2ab + {b}^{2} + ab + 4) \\ = (a + b - 2) ({a}^{2} + {b}^{2} + 3ab + 4)$