Question

factorise
$\frac{1}{2} x ^{2} - 3x + 4$
​

Answer 1

Step-by-step explanation:

$\frac{1 {x}^{2} }{2} - 3x + 4$

$= \frac{1 {x}^{2} - 6x + 8}{2}$

$= \frac{ {x}^{2} - 6x + 8}{2}$

Let's Split the middle term

$= \frac{{x}^{2} - 4x - 2x + 8}{2}$

$= \frac{x(x - 4) - 2(x - 4)}{2}$

$= \frac{(x - 4)(x - 2)}{2}$

$= \frac{(x - 4)}{2} \times \frac{(x - 2)}{2}$

Please solve it Further