Question

factorise:-
$\frac{4}{{c}^{2} } - \frac{2}{cd} + \frac{1}{4 {d}^{2} }$
​

Answer 1

Step-by-step explanation:

$\frac{4}{ {c}^{2} } - \frac{2}{cd} + \frac{1}{4 {d}^{2} }$

$= ( { \frac{2}{c}) }^{2} - 2 \times \frac{2}{c} \times \frac{1}{2d} + ( { \frac{1}{2d}) }^{2}$

$= ( { \frac{2}{c} - \frac{1}{2d} })^{2}$