factorise
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Answered by
57
Hi ,
x^6/343 + 343/x^6
= ( x² )³/7³ + 7³/( x² )³
= ( x²/7 )³ + ( 7/x² )³
**************************
We know the algebraic identity,
x³ + y³ = ( x + y ) [ x² - xy + y² ]
********************************
= (x²/7 + 7/x²)[(x²/7)²-(x²/7)(7/x²)+(7/x²)²]
= (x²/7+7/x²)[ x⁴/49- 1 + 49/x⁴ ]
I hope this helps you.
: )
x^6/343 + 343/x^6
= ( x² )³/7³ + 7³/( x² )³
= ( x²/7 )³ + ( 7/x² )³
**************************
We know the algebraic identity,
x³ + y³ = ( x + y ) [ x² - xy + y² ]
********************************
= (x²/7 + 7/x²)[(x²/7)²-(x²/7)(7/x²)+(7/x²)²]
= (x²/7+7/x²)[ x⁴/49- 1 + 49/x⁴ ]
I hope this helps you.
: )
Answered by
36
hope it's helps
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