Question

Factorise :
$\large\bold{16{w}^{3} - {u}^{4} {w}^{3} }$

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Answer 1

Step-by-step explanation:

16w³-4u⁴w³

4w³(4-u⁴)

4w³(2-u²)(2+u²)

Answer 2

Answer:

$w ^{3} (16 - {u}^{4}) \\ w ^{3}(4 + {u}^{2 })(4 - {u}^{2} ) \\ w ^{3} (4 + {u}^{2})(2 + u)(2 - u)$

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