Question

Factorise: $p^{2}$ - 3pq + 2$q^{2}$

Answer 1

Answer:

The answer is :-

$(p - 2q)(p - q)$

Step-by-step explanation:

${p}^{2} - 3pq + 2 {q}^{2} \\ = {p}^{2} - 2pq - pq + 2 {q}^{2} \\ =p (p - 2q) - q( p - 2q) \\ = (p - 2q)(p -q )$

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Answer 2

Step-by-step explanation:

${p}^{2} - 3pq + 2 {q}^{2} \\ = {p}^{2} - 2pq - pq + 2 {q}^{2} \\ = p(p - 2q) + q(p -2 q) \\ = (p - 2q)(p + q)$

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