Math, asked by IshikaSarkar, 9 months ago

Factorise:
p  {}^{4}   - 256

Answers

Answered by Anonymous
3

Answer:

Hey dude!

Your answer (p+2)(p-2)(p^2 + 4)

Step-by-step explanation:

 {p}^{4}  - 256

 {p}^{4}  - {4}^{4}

 ({p}^{2})^{2} - ({2}^{2})^{2}

 ({p}^{2})^{2} - {4}^2

By using algebraic identity a^2 - b^2 = (a+b)(a-b), we get:

 ({p}^{2}+4)({p}^{2}-4)

 ({p}^{2}+4)({p}^{2}-{2}^{2})

 ({p}^{2}+4)(p+2)(p-2)

 (p+2)(p-2)({p}^{2}+4)

Hope it helps,

And,

Don't forget to follow me and choose this answer as the brainliest one.

Answered by Anonymous
10

Answer :D

p⁴ - 256

(p)⁴ - (4)⁴

(p - 4)⁴

(p - 4) (p + 4) (p² - 16)

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