Question

factorise
$\sf{}a-b-4{a}^{2} +4 {b}^{2}$
​

Answer 1

a - b - 4a ² + 4b²

solution

-4a ² + a - b + 4b

( - a + b ) ( 4a + 4b - 1 )

Answer 2

Required Answer:-

Given To Factorise:

• a - b - 4a² + 4b²

Solution:

We have,

a - b - 4a² + 4b²

= a - b - 4(a² - b²)

We know that,

➡ a² - b² = (a + b)(a - b)

So,

a - b - 4(a² - b²)

= 1(a - b) - 4(a + b)(a - b)

Taking (a - b) as common, we get,

= (a - b)[1 - 4(a + b)]

= (a - b)(1 - 4a - 4b)

★ Hence, the factorised form of the polynomial is (a - b)(1 - 4a - 4b)

Answer:

• Factorised form is (a - b)(1 - 4a - 4b)