Question

factorise
$\sqrt{2} {y}^{2} + 8y + 6 \sqrt{2}$
​

Answer 1

Answer:

$\large\bold\red{(y + \sqrt{2} )( \sqrt{2} y + 6)}$

Step-by-step explanation:

Given,

$\sqrt{2} {y}^{2} + 8y + 6 \sqrt{2}$

To factorise the given expression,

We may simplify it as,

$= \sqrt{2} {y}^{2} + (2y + 6y) + 6 \sqrt{2} \\ \\ = \sqrt{2} {y}^{2} + 2y + 6y + 6 \sqrt{2}$

Further,

Taking the common terms,

We get,

$= \sqrt{2} y(y + \sqrt{2} ) + 6(y + \sqrt{2} )$

Again,

Taking out common terms,

We get,

It's factorisation as,

$\large \boxed{\bold{(y + \sqrt{2} )( \sqrt{2} y + 6)}}$