Question

factorise
$x^{2} + (1 \div 4) - (1 \div 8)$
​

Answer 1

hii mate ❤..

Answer:

x²+x/4-1/8=(x+1/2)(x-1/4)

Explanation:

Given quadratic polynomial:

x²+x/4-1/8

Splitting the middle term,weget

=x²+x/2-x/4-1/8

=x(x+1/2)-1/4(x+1/2)

=(x+1/2)(x-1/4)

Therefore,

x²-x/4-1/8=(x+1/2)(x-1/4)

•••

Answer 2

Hii ☺️

you are welcome in my ans

x^2 + 1/4 - 1/8

= x^2 + 1/8

= x^2 - (-1/8)

= x^2 - sqrt (-1/8)

= (x - 1/2sqrt2 *i )(1 + 2sqrt 2 *i)

where i is iota whose value is

=>i^2 = -1

= > i = sqrt(- 1)

i called imagnary root

______/\_____✊✌️

Hope it may helps you