Question

Factorise :
${x}^{2} + 3 \sqrt{3x } + 6$

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Answer 1

HI USER ✌

HERE'S YOUR ANSWER ⤵⤵⤵⤵

⭕X^2+3√3X+6

⚫X^2+√3X+2√3X+6

⚫X(X+√3)+2√3(X+√3)

⚫(X+2√3)(X+√3) are the factors

VALUE OF 'X' IS

↪-2√3 and -√3

HOPE IT MAY HELPS UH ❤✌

Answer 2

Here Is Your Ans Dear ⤵

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${x}^{2} + \sqrt[3]{3} + 6 \\ {x}^{2} + \sqrt[2]{3} x + \sqrt{3} x + 6 \\ x(x + \sqrt[2]{3} ) + \sqrt{3} (x + \sqrt[2]{3} ) \\ hence \: x = \sqrt[ - 2]{3} and \: x = - \sqrt{3}$

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