Question

Factorise
$( {x}^{2} - 6x)^{2} -$
$8( {x}^{2} - 6x + 8) - 64$

​

Answer 1

Answer:

$answer \: \: \: \: \: \: \: \: ( {x}^{2} - 6x + 8)( {x}^{2} - 6x - 16)$

Step-by-step explanation:

$let \: {x}^{2} - 6x = y \\ then \: \: \: the \: given \: expression \: becomes \\ {y}^{2} - 8(y + 8) - 64 \\ = { {y}^{2} - 8y - } - 64 - 64 \\ = {y}^{2} - 8y - 128 \\ =(y + 8)(y - 16) \\ = ( {x}^{2} - 6x + 8)( {x}^{2} - 6x - 16)$