Question

Factorise $x^2 + 9x + 18$

Answer 1

${x}^{2} + 9x + 18 \: = (9 \times 2) = 18 \: and(6x + 3x) =9x \\ ( {x}^{2} + 6x) + (3x + 18 \: \: (split \: middle \: terms)\\ x(x + 6) 3(x + 6) \\ (x + 6)(x + 3)$

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Answer 2

Question:

Factorise $x^{2} +9x+18$

Step-by-step explanation:

STEP 1

split $9x$ such that the sum of 2 digit is 9 and multiplication is 18

 $x^{2} +3x+6x+18=0$

STEP 2

take comman

$x(x+3)+6(x+3)=0$

$(x+3)(x+6)=0$

so here $x+3=0$ or$x+6=0$

so $x=-3$ Or $x=-6$