Factorise :-
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Answered by
27
Answer:
Factorise x3-3x2-9x-5. hence,
(x +1), (x -5) and (x +1) are the factors of given polynomial . ∴
By Factor Theorem, x - (- 1), i.e., (x + 1) is a factor of p(x). = (x + 1)(x - 5)(x + 1).
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Answered by
9
Answer:
x³-3x²−9x-5=x²(x+1)-4x(x+1)-5(x+1)
=(x+1)(x²-4x-5)
=(x+1)[x²-5x+x-5]
=(x+1)[x(x-5)+(x-5)]
=(x-1)(x-5)(x+1)
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