Question

factorise :
$x ^{3} + 4x ^{2} + 5x + 2$
Please help want the correct answer now​

Answer 1

Step-by-step explanation:

Let f(x)=x

3

−4x

2

+5x−2

Sum of the coefficients =1−4+5−2=0

∴(x−1) is a factor.

Remainder =0

f(x)=x

3

−4x

2

+5x−2

=(x−1)(x

2

−3x+2)

=(x−1)(x−1)(x−2)

=(x−1)

2

(x−2)

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