Question

factorise
${x}^{6} - 7 {x}^{3} + 8$ correct answer will be marked as brainliest​

Answer 1

${x}^{6} - 7 {x}^{3} + 8$

= (x³)² - 7 (x³) + 8

= (x³ - 8) (x³ + 1)

= (x³ - 2³) ( x³ + 1³)

We know that ;

» a³+b³ = (a+b) (a² -ab + b²) And;

»a³ - b ³ = ( a - b ) (a² +ab + b²)

So;

= (x - 2) (x² + 2x + 4 ) (x +1 )(x² - x +1)