factorise
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Answered by
104
Answer :
Now,
x (x³ - y³) + 3xy (x - y)
= x (x - y) (x² + xy + y²) + 3xy (x - y)
= x (x - y) (x² + xy + y² + 3y),
which is the required factorization.
#MarkAsBrainliest
Now,
x (x³ - y³) + 3xy (x - y)
= x (x - y) (x² + xy + y²) + 3xy (x - y)
= x (x - y) (x² + xy + y² + 3y),
which is the required factorization.
#MarkAsBrainliest
Answered by
112
x(x³-y³) + 3xy(x - y)
=> x[ (x³ - y³) +3y(x - y)]
=> x [ (x - y)(x² + xy + y²) + 3y(x - y)]
=> x(x - y) [ x² + y² +xy + 3y]
=> (x)(x - y) (x² + y² + xy + 3y)
I hope this will help you
(-:
abhi569:
Thanks for choosing a brainlist answer
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