Question

Factorise the 2x-32x^5

Answer 1

= 2x (1-16x^4)
=2x {(1)^2 -(4x^2)^2}
=2x (1+4x^2)(1 - 4x^2)
=2x (1+4x^2){(1)^2-(2x)^2}
=2x (1+4x^2)(1+2x)(1-2x)

Answer 2

Answer:

$Factors \:of \:2x-32x^{5}\\=2x(1+4x^{2})(1+2x)(1-2x)$

Step-by-step explanation:

$Given \: 2x-32x^{5}$

\* we know the algebraic identity:

a²-b²=(a+b)(a-b)*/

=$2x-2x\times(2x)^{4}\\=2x[1-(2x)^{4}]\\=2x[1^{2}-\big((2x)^{2}\big)^{2}]\\=2x[1+(2x)^{2}][1^{2}-(2x)^{2}]\\=2x(1+4x^{2})(1+2x)(1-2x)$

Therefore,

$2x-32x^{5}\\=2x(1+4x^{2})(1+2x)(1-2x)$