Math, asked by anniejohnymj, 3 months ago

factorise the 64z3-729m3​

Answers

Answered by kavinsiddhu758
1

Answer:

64z^3-729m^3\\= \left(4z\right)^3-\left(9m\right)^3\\= \left(4z-9m\right)\left(4^2z^2+4\cdot \:9zm+9^2m^2\right)\\= \left(4z-9m\right)\left(16z^2+36zm+81m^2\right)

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Answered by anshika3834
1
Hope this helps...........
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