Question

factorise the 64z3-729m3​

Answer 1

Answer:

$64z^3-729m^3\\= \left(4z\right)^3-\left(9m\right)^3\\= \left(4z-9m\right)\left(4^2z^2+4\cdot \:9zm+9^2m^2\right)\\= \left(4z-9m\right)\left(16z^2+36zm+81m^2\right)$

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Answer 2

Hope this helps...........