Question

factorise the above mentioned​

Answer 1

Answer:

$= 2 {x}^{2} - x + \frac{1}{8} \\ \\ = \frac{16 {x}^{2} - 8x + 1 }{8} \\ \\ = \frac{16 {x}^{2} - (4 + 4)x + 1}{8} \\ \\ = \frac{16 {x}^{2} - 4x - 4x - 1}{8} \\ \\ = \frac{4x(4x - 1) - 1(4x - 1)}{8} \\ \\ = \frac{(4x - 1)(4x - 1)}{8} \\ \\ = \frac{1}{8} {(4x - 1)}^{2}$