Question

factorise the above question

Answer 1

Hello there!
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You can factorise the given question as follows:

$= 2(ab + cd) - {a}^{2} - {b}^{2} + {c}^{2} + {d}^{2} \\ = {c}^{2} + 2cd + {d}^{2} - {a}^{2} + 2ab - {b}^{2} \\ = {(c + d)}^{2} - {(a - b)}^{2} \\ = (c + d + (a - b))(c + d - (a - b)) \\ = (c + d + a - b)(c + d - a + b)$
Hence we have factorised the given equation!
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Hope this helps!