Question

factorise the binomial with its identity
13) 49a²-100​

Answer 1

$49 {a}^{2} - 100 \\ = {(7a)}^{2} - {(10)}^{2} \\ = (7a - 10)(7a + 10) \\ (we \: kno \:w \: that \: {x}^{2} - {y}^{2} = (x - y)(x + y) |)$