Question

Factorise the equation

1+ 64x³​

Answer 1

Step-by-step explanation:

$\large\implies{\sf }$ We have 1+64x³

$\large\implies{\sf }$ (1)³+(4x)³

$\large\implies{\sf }$ (1+4x) (1-4x+16x²)

Since, (a³+b³)= (a+b) (a²-ab+b²)

Answer 2

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$\huge\boxed{ANSWER}$

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1+64x³

=1³+(4x)³

=(1+4x)(1²-(4x×1)+(4x)²)

=(1+4x)(1-4x+16x²)

Thus factors of given p(x) are

(1+4x) and (1-4x+16x²)