factorise the equation
28a²b²-7
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HEY Buddy....!! here is ur answer
Given that : 28a²b²–7
=> 7(4a²b²–1)
=> 7[(2ab)²–(1)²]
[ As we know that : a²–b² = (a+b)(a–b) ]
=> 7(2ab+1)(2ab–1)
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
Given that : 28a²b²–7
=> 7(4a²b²–1)
=> 7[(2ab)²–(1)²]
[ As we know that : a²–b² = (a+b)(a–b) ]
=> 7(2ab+1)(2ab–1)
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
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