Question

factorise the equation

Answer 1

hey!

#Ur Ans

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put the value of X is 1 which is factor of 120

now

$(1 {)}^{3} - 23( {1)}^{2} + 142 - 120 \\ \\ = > 1 - 23 + 142 - 120 \\ \\ = > 143 - 143 = 0 \\ \\ so \: (x - 1) \: is \: a \: factor \\ \: of \: the \: eqution \\ \\ now \\ \\ {x}^{2} (x - 1) - 22x(x - 1) + 120(x - 1) \\ \\ = > (x - 1)( {x }^{2} - 22x + 120) \\ \\ factorise \\ \\ = > (x - 1)( {x}^{2} - 12x - 10x + 120) \\ \\ = > (x - 1)(x(x - 12) -10 (x - 12)) \\ \\ = > (x - 1)(x - 10)(x - 12) \: ans$