Question

factorise the equation by regrouping-
(2x - 3y ) (a - b) + ( 3y - 2x ) (3a - b)​

Answer 1

Answer:

-2a(2x-3y)

Step-by-step explanation:

(2x - 3y)(a - b)+( 3y - 2x )(3a - b)

= (2x-3y)(a-b)-(2x-3y)(3a-b)

= (2x-3y)[(a-b)-(3a-b)]

= (2x-3y)(a-b-3a+b)

= (2x-3y)(-2a)

= -2a(2x-3y)

Therefore,

(2x - 3y)(a - b)+(3y - 2x )(3a - b)

= -2a(2x-3y)

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Answer 2

$\huge\sf{Answer:-}$

$(2x - 3y)(a - b) + (3y - 2x)(3a - b) \\ = (2x - 3y)(a - b) - (2x - 3y)(3a - b) \\ = (2x - 3y)(a - b) - (3a - b) \\ = (2x - 3y)(a - b) - (3a + b) \\ = (2x - 3y)( - 2a) \\ = - 2a(2x - 3y)$

So,

$= (2x - 3y)(a - b) + (3y - 2x)(3a - b) \\ = - 2a(2x - 3y)$