Factorise the equation p^2 – √3 p – 6
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Answer:
(p-2√3)(p+√3)
Let's solve step by step:
p² - √3p - 6
- hear we have to factors of 6 such that whose difference is -√3
- 6 = 3 × 2 = 2×√3×√3
- to get -√3 with 2×√3×√3 we will do -2√3 + √3
-2√3 + √3 = -√3
= p² - 2√3p + √3p - 6
= p (p - 2√3) + √3 (p - 2√3)
= (p - 2√3)(p + √3)
cheese
:)
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