Question

factorise the equation
x^2 + (2-root5)x - 2root5 =0​

Answer 1

Step-by-step explanation:

$\huge \red{Solution}$

x^2 + (2-root5)x - 2root5 =0

Here,a=1,b=(2-root5),c=2root5

b^2-4ac=(2-root5)^2-4(1)(2root5)

= 4-4root5+5-8root5

= 4-12root5

x=-b+root(4-12root5)/2a or -b-root4-12root5/2a

x = -2+root5-(4-12root5)/2 or

-2-root5-(4-12root5)/2