Question

Factorise The expression —4a² + 4ab—4ca

Answer 1

Answer:

-4a(a-b+c)

Step-by-step explanation:

We have, 4a

2

=2×2×a×a,

4ab=2×2×a×b

and,4ca=2×2×c×a

The three terms have 2, 2 and a as common facotrs

−4a

2

+4ab−4ca=−(2×2×a×a)+(2×2×a×b)−(2×2×c×a)

=2×2×a×(−a+b−c)

=4a(−a+b−c)

=−4a(a−b+c)

Answer 2

1. xyz(x+y+z)
2. x²yz+xy²z+xyz²= (xyz) (x+y+z)