factorise the expression:9y(6y-5z)-6a(6y-5z)
please answer urgent
Answers
Step-by-step explanation:
♐Step by Step Solution:
More Icon
☯️STEP-1
:
Equation at the end of step 1
(((6•(y5))•(z3))-(9•(y2)))•(0-5yz4)
☯️ STEP -2
:
Equation at the end of step
2
:
(((6•(y5))•(z3))-32y2)• -5yz4
☯️STEP -3
:
Equation at the end of step 3
:
(((2•3y5) • z3) - 32y2) • -5yz4
☯️STEP-4
:
☯️STEP-5
:
Pulling out like terms
5.1 Pull out like factors :
6y5z3 - 9y2 = 3y2 • (2y3z3 - 3)
Trying to factor as a Difference of Cubes:
5.2 Factoring: 2y3z3 - 3
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : 2 is not a cube !!
Multiplying exponential expressions :
5.3 y2 multiplied by y1 = y(2 + 1) = y3
Final result :
⭐ ( -3•5y3z4) • (2y3z3 - 3)
Answer:
An integer (from the Latin integer meaning "whole") is colloquially defined as a number that can be written without a fractional component. For example, 21, 4, 0, and −2048 are integers, while 9.75, 512, and √2 are not.