Question

factorise the expression and divide(48x^4-27x^2y^2)÷3(4x+3y)
pls answer this question with proper steps.​

Answer 1

Answer:

$\frac{ \:(48x^4-27x^2y^2)}{ 3(4x+3y) } \\ = \frac{3 {x}^{2} (16 {x}^{2 } - 9 {y}^{2} )}{ 3(4x+3y)} \\ = \frac{3 {x}^{2} (4x + 3y)(4x - 3y)}{3(4x + 3y)} \\ = {x}^{2} (4x - 3y)$