Factorise the expression and divide them (x2-12x -45)(x+1)(x2+4x+3).Is (x+1) a factor of the given expression.
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Answer:
We have g(x)=2x−1
⇒2x−1=0
⇒2x−1⇒x=
2
1
Remainder =p(
2
1
)
=4(
2
1
)
3
−12(
2
1
)
2
+14(
2
1
)−3
=(
8
1
)−12(
4
1
)+7−3
=
2
1
−3+7−6=
2
1
−2=
2
−3
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