Math, asked by savleen, 1 year ago

factorise the expression by regrouping:. 1) ab^2-bc^2-ab+c^2. 2) (p^2-4p^2)-16(p^2-4p)-q(p^2-4p)+16p^2q-64pq


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Answered by HappiestWriter012
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=(p^2-4p^2)-16(p^2-4p)-q(p^2-4p)+16p^2q-64pq

=(p^2-4p^2)-16(p^2-4p)-q(p^2-4p)+16q(p^2-4p)

= (p^2-4p^2)-16(p^2-4p)
+(16q-q)( p^2-4p)
= (p^2-4p^2)-16(p^2-4p)
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