Question

Factorise the expression completely (a+3)^2-9

Answer 1

Answer:

a and a+6 is the correct answer

Step-by-step explanation:

(a+3)²−9 is a difference of squares

and in general factorises as

∙xa2−b2=(a−3)(a+3)

here a=x and b=3

⇒(a+3)²−9=(a+3−3)(a+3+3)

=>(a),(a+6)

Answer 2

$\tt\huge\purple{hello!!!}$

HERE IS UR ANSWER

$_____________________________$

$(a + 3) {}^{2} - 9$

${{(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy}$

$( {a}^{2} + {3}^{2} + 2 \times 3 \times a) - 9 \\ = {a}^{2} + 9 - 9 + 6a \\ = {a}^{2} + 6a \\ = a(a + 6)$