Question

Factorise the expression given in the figure.​

Answer 1

Answer:

(x)(x-1)(x+1)(4x-5)

Step-by-step explanation:

$(x^{2} -x)(4x^{2} -4x-5)\\=>x(x-1)(4x^{2}+4x-5x-5)\\=>x(x-1)[4x(x+1)-5(x+1)]\\=>x(x-1)(x+1)(4x-5)\\=>(x)(x-1)(x+1)(4x-5)$

Answer 2

Answer:

\begin{gathered}(x^{2} -x)(4x^{2} -4x-5)\\= > x(x-1)(4x^{2}+4x-5x-5)\\= > x(x-1)[4x(x+1)-5(x+1)]\\= > x(x-1)(x+1)(4x-5)\\= > (x)(x-1)(x+1)(4x-5)\end{gathered}(x2−x)(4x2−4x−5)=>x(x−1)(4x2+4x−5x−5)=>x(x−1)[4x(x+1)−5(x+1)]=>x(x−1)(x+1)(4x−5)=>(x)(x−1)(x+1)(4x−5)