Question

Factorise thE expression (x- 2y upon 3) cube

Answer 1

HEYA!!!!

YOUR ANSWER:
By using the identity:

${(x - y)}^{3} = > {x}^{3} - {y}^{3} - 3xy$

We can solve this question.

Your question reads like this:

${(x - 2y \div 3})^{3}$

By solving it further through identity, we get:
${x}^{3} - {(2y)}^{3} - 3(x)(2y) \\ = > {x}^{3} - 8 {y}^{3} - 6xy$

HOPE IT HELPS!!!!

Answer 2

${(x - \frac{2y}{3}) }^{3} \\ use \: the \: identity \\ {(a - b)}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} ) \\ = (x - \frac{2y}{3} )( {x}^{2} + \frac{2xy}{3} + \frac{4 {y}^{2} }{9} )$