Question

factorise the expression
x²+3x-10
​

Answer 1

$\rm \red{factorise : \: \: {x}^{2} + 3x - 10 }$

$\sf{ \pink{step \: i : } \: multiply \: the \: first \: term \: and \: last \: term}$

$\sf{ \pink{step \: ii :} split \: the \: middle \: term}$

$\sf{ \pink{step \: iii : }take \: the \: common \: and \: make \: them \: equal \: to \: 0}$

$\mathsf{let \: f(x) \: = \: {x}^{2} + 3x - 10}$

$\mathsf{f(x) = 0}$

$\sf{ {x}^{2} + 3x - 10 = 0}$

$\sf{ {x}^{2} + 5x - 2x - 10 = 0}$

$\sf{x(x + 5) - 2(x + 5) = 0}$

$\mathsf{(x + 5)(x - 2) = 0}$

$\sf{x + 5 = 0} \: \: {\huge{|}} \: \: \sf{x - 2 = 0}$

$\sf{x = - 5 \: and \: 2}$

$\sf \red{factors \: of \: {x}^{2} + 3x - 10 \: \: are \: - 5 \: and \: 2 }$

Answer 2

Step-by-step explanation:

x²+3x-10=0

x²+5x-2x-10=0

x(x+5)-2(x+5)=0

(x+5)(x-2)=0

x= -5,2