Question

Factorise the expressions 7p2+21q2​

Answer 1

Answer:

$7[(p+3q)^{2} - 6pq]$

Step-by-step explanation:

$7p^{2} + 21q^{2}$

$7(p^{2} +3q^{2})$

$7[(p+3q)^{2} - 6pq]$ [∵ $(a+b)^{2} = a^{2} + b^{2} + 2ab$]

Answer 2

Answer:

$7( ({p + \sqrt{3} q})^{2} - 2 \sqrt{3} pq)$

Step-by-step explanation:

$7 {p}^{2} + 21 {q}^{2} \\ = 7( {p}^{2} + 3 {q}^{2} ) \\ = 7( ({p + \sqrt{3} q})^{2} - 2 \sqrt{3} pq)$

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