Question

factorise the expressions and divide them as directed. 9pq(q²-6q-16)\3p(q-8)​ ​

Answer 1

Answer:

$\frac{9pq(q^{2}-6q-16)}{3p(q-8)}=\frac{3q(q+2)}{p}$

Step-by-step explanation:

$\frac{9pq(q^{2}-6q-16)}{3p(q-8)}\\=\frac{3q(q^{2}-8q+2q-16)}{p(q-8)}\\=\frac{3q[q(q-8)+2(q-8)}{p(q-8)}\\=\frac{3q(q-8)(q+2)}{p(q-8)}\\=\frac{3q(q+2)}{p}$

Therefore,

$\frac{9pq(q^{2}-6q-16)}{3p(q-8)}=\frac{3q(q+2)}{p}$

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