Question

factorise the expressions by regrouping the terms. (a-2b)²+3a-b​

Answer 1

Answer:

Step-by-step explanation:

(a+2b)(3a+b)-(a+b)(a+2b)+(a+2b)²

=(3a²+ab+6ab+2b²)-(a²+2ab+ab+2b²)+(a²+4ab+4b²)

=(3a²+7ab+2b²)-(a²+3ab+2b²)+(a²+4ab+4b²)

=3a²+7ab+2b²-a²-3ab-2b²+a²+4ab+4b²

=3a²-a²+a²+7ab-3ab+4ab+2b²-2b²+4b²

=3a²+8ab+4b²

=3a²+6ab+2ab+4b²

=3a(a+2b)+2b(a+2b)

=(a+2b)(3a+2b)

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Answer 2

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