Question

factorise the expressions of x^2+y^2+z^2÷4+2xy_yz_zx

Answer 1

x2+y2+z2/4+2xy-yz-zx 

Final result :

4x2 + 8xy - 4xz + 4y2 - 4yz + z2 ———————————————————————————————— 4

Step by step solution :

Step  1  :

z2 Simplify —— 4

Equation at the end of step  1  :

z2 (((((x2)+(y2))+——)+2xy)-yz)-xz 4

Step  2  :

Rewriting the whole as an Equivalent Fraction :

 2.1   Adding a fraction to a whole 

Rewrite the whole as a fraction using  4  as the denominator :

x2 + y2 (x2 + y2) • 4 x2 + y2 = ——————— = ————————————— 1 4
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Answer 2

Answer:

(x+y-z/2) (x+y-y/2)

Step-by-step explanation:

=(x) ^2+(y) ^2+(z/2)^2+(2×x×y) -(2×y×z/2)-(2×z/2×x)

=(x+y -z/2) (x+y-z/2) Answer

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