Question

factorise the expressions
$39y^{3} (2(5y - 7) (5y + 7)) \div 26y ^{2} (5y + 7)$
​

Answer 1

Answer:

the ans is =3y(5y−7)

Step-by-step explanation:

39y

3

(50y

2

−98)÷26y

2

(5y+7)

=

26y

2

(5y+7)

39y

3

(50y

2

−98)

=

26y

2

(5y+7)

39y

3

(5×5×2y

2

−7×7×2)

=

26y

2

(5y+7)

39y

3

×2(5y)

2

−(7)

2

=

26y

2

(5y+7)

39y

3

×2(5y+7)(5y−7)

=3y(5y−7)